[أحـمـد ظـافـر]

المشاركة الأصلية كتبت بواسطة Mr.Ahmad يبدوا أني حليت السؤال في الأعلى بغير المطلوب في السؤال ,, الحل على كلام السؤال : الحل : public class first { public static void main(String[] args) { int n = Integer.parseInt(args[0].toString()); String box = "1"; int now = 0,total = 0; int i = 1; while ( (i-1) < n) { if (i == 1) {now = 1;total = 1;i++;} else { now = i; total += i; box += " + " + now; i++; } System.out.println(box + " = " + total); } } } تجربة البرنامج ,, ( الـ args[0] يساوي 7 ) . النتيجة : run: 1 = 1 1 + 2 = 3 1 + 2 + 3 = 6 1 + 2 + 3 + 4 = 10 1 + 2 + 3 + 4 + 5 = 15 1 + 2 + 3 + 4 + 5 + 6 = 21 1 + 2 + 3 + 4 + 5 + 6 + 7 = 28 BUILD SUCCESSFUL (total time: 0 seconds)

حل ممـتـاز ,,

هذا أيــضــا حـل آآآخــر :

 
public class SummationProblem {
    public static void main(String [] args)
    {
        int n = Integer.parseInt(args [0]);
        System.out.println('\t' +"*   "+ " YOU PUT THE NUMBER IS = " + n );
        System.out.println('\t'+"*   "+ "  I WILL SUM ALL NUMBERS BETWEEN 0 AND "+n+",:-");
        long sum = 0;
        while(n > 0)
        {
        System.out.print(" "+n + " + ");
        sum += n;
        n--;
        }
        System.out.println(" =  " + sum);
        System.out.println('\t'+"*  "+" THE SUM OF ALL NUMBERS IS = " + sum);
    }
 }

 
 /*Other Soluation:
        public class SummationProblem
{
    public static void main(String [] args)
    {
             int n = Integer.parseInt(args[0]);
             int i=1;
             while(i <= n)
            {
                System.out.print(i + " + ");
                i++;
             }
             System.out.print(" =  ");
            int x = Integer.parseInt(args[0]);
            long sum = 0;
            i=0;
            while(i <= x)
            {
                sum += x;
                i++;
             }
            System.out.print(sum/2 + "  ");
     }
}
        */////