[Dr.emma]

Find h'(1) given that f(1) = -6, f '(1) = -2, g(1) = -5, and g'(1) = 6.
(a) h(x) = 2f(x) - 3g(x)
h'(1) = 1

(b) h(x) = f(x)g(x)
h'(1) = 2

(c) h(x) = f(x)

g(x)h'(1) = 3

(d) h(x) = g(x)

4 + f(x)h'(1) = 4