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Find h'(1) given that f(1) = 4, f '(1) = -2, g(1) = 3, and g'(1) = -2.
(a) h(x) = 5f(x) - 3g(x)
h'(1) =

(b) h(x) = f(x)g(x)
h'(1) =

(c) h(x) = f(x)

g(x)
h'(1) =

(d) h(x) = g(x)

5 + f(x)
h'(1) =