[Rose soft]

Find h'(1) given that f(1) = -4, f '(1) = -3, g(1) = 3, and g'(1) = 4. (a) h(x) = 3f(x) - 2g(x)
h'(1) = 1

(b) h(x) = f(x)g(x)
h'(1) = 2

(c) h(x) = f(x)

g(x)h'(1) = 3


(d) h(x) = g(x)

1 + f(x)h'(1) = 4