[الشيمآء]

wa 3alykom As-salam.,

find dy/dx .,
y sin(1/y) = 1 - xy

sin(1/y)dy/dx + {[y][-1/y^2][cos(1/y)]dy/dx} = - y - xdy/dx
sin(1/y)dy/dx - {[1/y][cos(1/y)]dy/dx} = - y - x dy/dx
sin(1/y)dy/dx - {[1/y][cos(1/y)]dy/dx} + x dy/dx = - y
dy/dx = {-y} / {[sin(1/y) - [(1/y][cos(1/y)] + [x]}

newa7ed ma8amat alma8am 3la y, wo ma8am alma8am bas6., so,

dy/dx = {-y^2} / {[ysin(1/y) - [(1/y][cos(1/y)] + [xy]}

:S
hope u got it

u can get a PDF file for al-exercises elly fe alketab here, but I'm not really sure that it works, so check it please and tell me f it doesn't

:)