[الشيمآء]

RoOoNa_91

3y^2=(2x-5)/(2x+5)
dy/dx = 10 / 3y(2x+5)^2

2y^5+9x^7 = 7y + 4x
dy/dx =(-63x^6+4)/(10y-7)
at (1,1) dy/dx = -59/3

y=x(9x^2+7)^1/2
dy/dx = (18x^2+7)/√(9x^2+7))
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