[الشيمآء]

RoOoNa_91

3y^2 = (2x-5)/(2x+5)
dy/dx = 10 / 3y(2x+5)^2

y= tan u
u = 5x+3
then y = tan (5x+3)
dy/dx = 5 sec^2(5x+3)
s
الـ ثيتآ = 0
dr/d0 = ( r^1/9 ) / (0^1/9 )
s
آخر سؤال ..
u = 6 - 7x/8
f(u) = u^-8
dy/dx = 7 ( 6 - 7x/8 )^-9