at constant temperature (isothermal) situation
p1v1 = p2v2
but v2 =(1/3) v1 =(1/3) vi
p2 = p1v1/v2 = pivi/(1/3)vi = 3pi
الاختـيـآر 4
3pi
at constant pressure (isobaric) situation
v1/v2 = t1/t2
t1 =23 +273 =296 k
t2 =(v2/v1) t1 =(115/90)*296 =378 k
t2 = 378 -273 =105 c
الاختيـآر 5
105
at constant volume (isochoric) situation
t1/t2 =p1/p2
t2 = (p2/p1)t1
but 800 torr = 1.0528 atm
t2 = (3/01.0528)*273 = 778 k
t2 =778 -273=505 c
الاختيـآر 5
505